Solve the equation for the person above!
Solve the equation for the person above!
Basically, post an equation and solve it, then make your own equation while MIXING the equation of the previous poster with yours. ( You can only add 2 more digits to the forumla )
Let me start =D
2 + 1 = ?
(p/s, I'm mathematically impaired)
Let me start =D
2 + 1 = ?
(p/s, I'm mathematically impaired)
You cannot say it doesn't exist if you haven't seen it. ~Zinrius
Re: Solve the equation for the person above!
2 + 1 = 3 ÷ (
(Note - the bracket is part of it)
Edit: Missed the 'Make your own and solve it' part.
3x ÷ 4 = 5
x = 6 1/3
(Note - the bracket is part of it)
Edit: Missed the 'Make your own and solve it' part.
3x ÷ 4 = 5
x = 6 1/3
Richard Dawkins wrote:I am against religion because it teaches us to be satisfied with not understanding the world.
Re: Solve the equation for the person above!
I have got one for you:
It is pretty simple.
EDIT: Actually it is not. I just did it, it is kind of a pain and wolfram gets a different answer than me, which is bad considering I have a calc. exam in a few hours....
I forgot to include the dx on the end of the integrand. It is pretty simple.
EDIT: Actually it is not. I just did it, it is kind of a pain and wolfram gets a different answer than me, which is bad considering I have a calc. exam in a few hours....
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Last edited by Hahsime on 14 Apr 2011, 10:24, edited 1 time in total.
Re: Solve the equation for the person above!
/me cracks knuckles. i LOVE intergrals.
(X^2)(X+2)^-1
now intergrate to get.
(1/3X^3)(1/-2 X+1)^-2
cant remember the area under a curve right now...
(X^2)(X+2)^-1
now intergrate to get.
(1/3X^3)(1/-2 X+1)^-2
cant remember the area under a curve right now...
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Re: Solve the equation for the person above!
Not quite. Hint: You have to do long division on the integrand to get it into the right form.vallorn wrote:/me cracks knuckles. i LOVE intergrals.
(X^2)(X+2)^-1
now intergrate to get.
(1/3X^3)(1/-2 X+1)^-2
cant remember the area under a curve right now...
Re: Solve the equation for the person above!
yeah its kind of difficult to see what im writing on the PC therefore i make mistakes like that... i think simply multiplying it out would work just as well but of course mr derp here forgot to do that .Hashime wrote:Not quite. Hint: You have to do long division on the integrand to get it into the right form.vallorn wrote:/me cracks knuckles. i LOVE intergrals.
(X^2)(X+2)^-1
now intergrate to get.
(1/3X^3)(1/-2 X+1)^-2
cant remember the area under a curve right now...
here goes Again:
(X^2)(X+2)^-1
hmm so im multiplying the second bracket by X^2...
lets see...
X^2+2X ??? i think... (kind of rusty with algebraic fractions like this)
then integrate...
1/3 X^3 + X^2
that better?
Lord_Mountbatten wrote:I didn't quite hear you over the sound of my eyebrow shooting into the sky.
OI YOU!
YES YOU!
WE HAVE A STEAM COMMUNITY GROUP!
JOIN US AND ADD PEOPLE FOR FUN TIMES!
CUT: Baldrick
Re: Solve the equation for the person above!
Not even close, are you sure you are integrating?vallorn wrote:yeah its kind of difficult to see what im writing on the PC therefore i make mistakes like that... i think simply multiplying it out would work just as well but of course mr derp here forgot to do that .Hashime wrote:Not quite. Hint: You have to do long division on the integrand to get it into the right form.vallorn wrote:/me cracks knuckles. i LOVE intergrals.
(X^2)(X+2)^-1
now intergrate to get.
(1/3X^3)(1/-2 X+1)^-2
cant remember the area under a curve right now...
here goes Again:
(X^2)(X+2)^-1
hmm so im multiplying the second bracket by X^2...
lets see...
X^2+2X ??? i think... (kind of rusty with algebraic fractions like this)
then integrate...
1/3 X^3 + X^2
that better?
I also forgot to add a dx on the end of the integrand
- DuplicateValue
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Re: Solve the equation for the person above!
Er, I haven't done one of those in a while, so this will probably be horribly wrong.
X^2/(X+2) dx
X^2 . 1/(X+2)
Let (X+2) = u
du/dx = X^2
du = X^2 dx
New Limits --->
u = (10)+2 = 12
u = (0)+2 = 2
1/u du
[lnu] (lims 12 and 2)
[ln12 - ln2]
[2.48490665 - 0.6931471806]
= 1.791759469
X^2/(X+2) dx
X^2 . 1/(X+2)
Let (X+2) = u
du/dx = X^2
du = X^2 dx
New Limits --->
u = (10)+2 = 12
u = (0)+2 = 2
1/u du
[lnu] (lims 12 and 2)
[ln12 - ln2]
[2.48490665 - 0.6931471806]
= 1.791759469
"He's like fire, and ice, and rage.
He's like the night, and the storm in the heart of the sun.
He's ancient and forever.
He burns at the centre of time and he can see the turn of the universe.
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Re: Solve the equation for the person above!
You need to split up the terms in the integrand to be able to integrate this.DuplicateValue wrote:Er, I haven't done one of those in a while, so this will probably be horribly wrong.
X^2/(X+2) dx
X^2 . 1/(X+2)
Let (X+2) = u
du/dx = X^2
du = X^2 dx
New Limits --->
u = (10)+2 = 12
u = (0)+2 = 2
1/u du
[lnu] (lims 12 and 2)
[ln12 - ln2]
[2.48490665 - 0.6931471806]
= 1.791759469
This is done using polynomial long division.
Once you get past that step it should look easy.
- DuplicateValue
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Re: Solve the equation for the person above!
Really? I was almost certain I was right there.Hashime wrote:You need to split up the terms in the integrand to be able to integrate this.
This is done using polynomial long division.
Once you get past that step it should look easy.
This is how I was shown how to integrate quotients at any rate.
Edit: Just to be clear, when I said X^2 . 1/X+2, I meant (X^2)(1/X+2).
"He's like fire, and ice, and rage.
He's like the night, and the storm in the heart of the sun.
He's ancient and forever.
He burns at the centre of time and he can see the turn of the universe.
And... he's wonderful."
Re: Solve the equation for the person above!
Here are the steps as an indefinite integral. You can see where one would put the numbers in.
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Re: Solve the equation for the person above!
OH GOD LOGARITHMS! /me dislikes this solution...
Lord_Mountbatten wrote:I didn't quite hear you over the sound of my eyebrow shooting into the sky.
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YES YOU!
WE HAVE A STEAM COMMUNITY GROUP!
JOIN US AND ADD PEOPLE FOR FUN TIMES!
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- Cyphafrost
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Re: Solve the equation for the person above!
This is a clever one of mine.
9x-7i > 3(3x-7u)
9x-7i > 3(3x-7u)
Spoiler! :
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Derp
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